10=0.25x^2

Solution for 10=0.25x^2 equation:

10=0.25x^2

We move all terms to the left:

10-(0.25x^2)=0

We get rid of parentheses

-0.25x^2+10=0

a = -0.25; b = 0; c = +10;
Δ = b2-4ac
Δ = 02-4·(-0.25)·10
Δ = 10
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{10}}{2*-0.25}=\frac{0-\sqrt{10}}{-0.5}
=-\frac{\sqrt{}}{-0.5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{10}}{2*-0.25}=\frac{0+\sqrt{10}}{-0.5}
=\frac{\sqrt{}}{-0.5}
$